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Solve for x (complex solution)
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t^{2}-33t+32=0
Substitute t for x^{5}.
t=\frac{-\left(-33\right)±\sqrt{\left(-33\right)^{2}-4\times 1\times 32}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -33 for b, and 32 for c in the quadratic formula.
t=\frac{33±31}{2}
Do the calculations.
t=32 t=1
Solve the equation t=\frac{33±31}{2} when ± is plus and when ± is minus.
x=-2ie^{\frac{\pi i}{10}} x=-2e^{\frac{\pi i}{5}} x=2ie^{\frac{3\pi i}{10}} x=2e^{\frac{2\pi i}{5}} x=2 x=-ie^{\frac{\pi i}{10}} x=-e^{\frac{\pi i}{5}} x=ie^{\frac{3\pi i}{10}} x=e^{\frac{2\pi i}{5}} x=1
Since x=t^{5}, the solutions are obtained by solving the equation for each t.
t^{2}-33t+32=0
Substitute t for x^{5}.
t=\frac{-\left(-33\right)±\sqrt{\left(-33\right)^{2}-4\times 1\times 32}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -33 for b, and 32 for c in the quadratic formula.
t=\frac{33±31}{2}
Do the calculations.
t=32 t=1
Solve the equation t=\frac{33±31}{2} when ± is plus and when ± is minus.
x=2 x=1
Since x=t^{5}, the solutions are obtained by evaluating x=\sqrt[5]{t} for each t.