Solve for x
x=-1
x=2
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t^{2}-31t-32=0
Substitute t for x^{5}.
t=\frac{-\left(-31\right)±\sqrt{\left(-31\right)^{2}-4\times 1\left(-32\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -31 for b, and -32 for c in the quadratic formula.
t=\frac{31±33}{2}
Do the calculations.
t=32 t=-1
Solve the equation t=\frac{31±33}{2} when ± is plus and when ± is minus.
x=2 x=-1
Since x=t^{5}, the solutions are obtained by evaluating x=\sqrt[5]{t} for each t.
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