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Solve for x (complex solution)
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t^{2}+4t+3=0
Substitute t for x^{5}.
t=\frac{-4±\sqrt{4^{2}-4\times 1\times 3}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 4 for b, and 3 for c in the quadratic formula.
t=\frac{-4±2}{2}
Do the calculations.
t=-1 t=-3
Solve the equation t=\frac{-4±2}{2} when ± is plus and when ± is minus.
x=-ie^{\frac{3\pi i}{10}} x=-e^{\frac{2\pi i}{5}} x=-1 x=ie^{\frac{\pi i}{10}} x=e^{\frac{\pi i}{5}} x=-\sqrt[5]{3}ie^{\frac{3\pi i}{10}} x=-\sqrt[5]{3}e^{\frac{2\pi i}{5}} x=-\sqrt[5]{3} x=\sqrt[5]{3}ie^{\frac{\pi i}{10}} x=\sqrt[5]{3}e^{\frac{\pi i}{5}}
Since x=t^{5}, the solutions are obtained by solving the equation for each t.
t^{2}+4t+3=0
Substitute t for x^{5}.
t=\frac{-4±\sqrt{4^{2}-4\times 1\times 3}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 4 for b, and 3 for c in the quadratic formula.
t=\frac{-4±2}{2}
Do the calculations.
t=-1 t=-3
Solve the equation t=\frac{-4±2}{2} when ± is plus and when ± is minus.
x=-1 x=-\sqrt[5]{3}
Since x=t^{5}, the solutions are obtained by evaluating x=\sqrt[5]{t} for each t.