Solve for x
x=-\sqrt[5]{10}\approx -1.584893192
x=-1
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t^{2}+11t+10=0
Substitute t for x^{5}.
t=\frac{-11±\sqrt{11^{2}-4\times 1\times 10}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 11 for b, and 10 for c in the quadratic formula.
t=\frac{-11±9}{2}
Do the calculations.
t=-1 t=-10
Solve the equation t=\frac{-11±9}{2} when ± is plus and when ± is minus.
x=-1 x=-\sqrt[5]{10}
Since x=t^{5}, the solutions are obtained by evaluating x=\sqrt[5]{t} for each t.
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