Solve x^frac{1{3}}(2y+7)-1/4(1-4y)leq47

$$x ^ { \frac { 1 } { 3 } } ( 2 y + 7 ) - \frac { 1 } { 4 } ( 1 - 4 y ) \leq 47$$

Solve for x

$$\left\{\begin{matrix}x\leq \frac{\left(\frac{189-4y}{2y+7}\right)^{3}}{64}\text{, }&y>-\frac{7}{2}\\x\geq \frac{\left(\frac{189-4y}{2y+7}\right)^{3}}{64}\text{, }&y<-\frac{7}{2}\\x\in \mathrm{R}\text{, }&y=-\frac{7}{2}\\x=\frac{\left(\frac{189-4y}{2y+7}\right)^{3}}{64}\text{, }&y\neq -\frac{7}{2}\end{matrix}\right.$$

Solve for y

$$\left\{\begin{matrix}y\geq -\frac{7\left(4\sqrt[3]{x}-27\right)}{4\left(2\sqrt[3]{x}+1\right)}\text{, }&x<-\frac{1}{8}\\y\leq -\frac{7\left(4\sqrt[3]{x}-27\right)}{4\left(2\sqrt[3]{x}+1\right)}\text{, }&x>-\frac{1}{8}\\y\in \mathrm{R}\text{, }&x=-\frac{1}{8}\\y=-\frac{7\left(4\sqrt[3]{x}-27\right)}{4\left(2\sqrt[3]{x}+1\right)}\text{, }&x\neq -\frac{1}{8}\end{matrix}\right.$$