Solve for x
x=-\frac{7}{1-8y}
y\neq \frac{1}{8}
Solve for y
y=\frac{1}{8}+\frac{7}{8x}
x\neq 0
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x-8xy=-7
Subtract 8xy from both sides.
\left(1-8y\right)x=-7
Combine all terms containing x.
\frac{\left(1-8y\right)x}{1-8y}=-\frac{7}{1-8y}
Divide both sides by -8y+1.
x=-\frac{7}{1-8y}
Dividing by -8y+1 undoes the multiplication by -8y+1.
8xy-7=x
Swap sides so that all variable terms are on the left hand side.
8xy=x+7
Add 7 to both sides.
\frac{8xy}{8x}=\frac{x+7}{8x}
Divide both sides by 8x.
y=\frac{x+7}{8x}
Dividing by 8x undoes the multiplication by 8x.
y=\frac{1}{8}+\frac{7}{8x}
Divide x+7 by 8x.
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