Solve for x
x=-\frac{8}{1-6y}
y\neq \frac{1}{6}
Solve for y
y=\frac{1}{6}+\frac{4}{3x}
x\neq 0
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x-6xy=-8
Subtract 6xy from both sides.
\left(1-6y\right)x=-8
Combine all terms containing x.
\frac{\left(1-6y\right)x}{1-6y}=-\frac{8}{1-6y}
Divide both sides by -6y+1.
x=-\frac{8}{1-6y}
Dividing by -6y+1 undoes the multiplication by -6y+1.
6xy-8=x
Swap sides so that all variable terms are on the left hand side.
6xy=x+8
Add 8 to both sides.
\frac{6xy}{6x}=\frac{x+8}{6x}
Divide both sides by 6x.
y=\frac{x+8}{6x}
Dividing by 6x undoes the multiplication by 6x.
y=\frac{1}{6}+\frac{4}{3x}
Divide x+8 by 6x.
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