Solve x=6-13/4+1/4x

$$x = 6 - \frac { 13 } { 4 } + \frac { 1 } { 4 } x$$

Solve for x

$$x = \frac{11}{3} = 3\frac{2}{3} \approx 3.666666667$$

Steps for Solving Linear Equation

Convert 6 to fraction \frac{24}{4}.

$$x=\frac{24}{4}-\frac{13}{4}+\frac{1}{4}x$$

Since \frac{24}{4} and \frac{13}{4} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{24-13}{4}+\frac{1}{4}x$$

Subtract 13 from 24 to get 11.

$$x=\frac{11}{4}+\frac{1}{4}x$$

Subtract \frac{1}{4}x from both sides.

$$x-\frac{1}{4}x=\frac{11}{4}$$

Combine x and -\frac{1}{4}x to get \frac{3}{4}x.

$$\frac{3}{4}x=\frac{11}{4}$$

Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}.

$$x=\frac{11}{4}\times \frac{4}{3}$$

Multiply \frac{11}{4} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{11\times 4}{4\times 3}$$

Cancel out 4 in both numerator and denominator.

$$x=\frac{11}{3}$$