Solve x=-11x+x^2-x

$$x = - 11 x + x ^ { 2 } - x$$

Solve for x

$$x=13$$

$$x=0$$

Steps Using Factoring

Combine -11x and -x to get -12x.

$$x=-12x+x^{2}$$

Add 12x to both sides.

$$x+12x=x^{2}$$

Combine x and 12x to get 13x.

$$13x=x^{2}$$

Subtract x^{2} from both sides.

$$13x-x^{2}=0$$

Factor out x.

$$x\left(13-x\right)=0$$

To find equation solutions, solve x=0 and 13-x=0.

$$x=0 x=13$$

Steps Using the Quadratic Formula

Combine -11x and -x to get -12x.

$$x=-12x+x^{2}$$

Add 12x to both sides.

$$x+12x=x^{2}$$

Combine x and 12x to get 13x.

$$13x=x^{2}$$

Subtract x^{2} from both sides.

$$13x-x^{2}=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$-x^{2}+13x=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 13 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-13±\sqrt{13^{2}}}{2\left(-1\right)}$$

Take the square root of 13^{2}.

$$x=\frac{-13±13}{2\left(-1\right)}$$

Multiply 2 times -1.

$$x=\frac{-13±13}{-2}$$

Now solve the equation x=\frac{-13±13}{-2} when ± is plus. Add -13 to 13.

$$x=\frac{0}{-2}$$

Divide 0 by -2.

$$x=0$$

Now solve the equation x=\frac{-13±13}{-2} when ± is minus. Subtract 13 from -13.

$$x=-\frac{26}{-2}$$

Divide -26 by -2.

$$x=13$$

The equation is now solved.

$$x=0 x=13$$

Steps for Completing the Square

Combine -11x and -x to get -12x.

$$x=-12x+x^{2}$$

Add 12x to both sides.

$$x+12x=x^{2}$$

Combine x and 12x to get 13x.

$$13x=x^{2}$$

Subtract x^{2} from both sides.

$$13x-x^{2}=0$$

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$-x^{2}+13x=0$$

Divide both sides by -1.

$$\frac{-x^{2}+13x}{-1}=\frac{0}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x^{2}+\frac{13}{-1}x=\frac{0}{-1}$$

Divide 13 by -1.

$$x^{2}-13x=\frac{0}{-1}$$

Divide 0 by -1.

$$x^{2}-13x=0$$

Divide -13, the coefficient of the x term, by 2 to get -\frac{13}{2}. Then add the square of -\frac{13}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-13x+\left(-\frac{13}{2}\right)^{2}=\left(-\frac{13}{2}\right)^{2}$$

Square -\frac{13}{2} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-13x+\frac{169}{4}=\frac{169}{4}$$

Factor x^{2}-13x+\frac{169}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{13}{2}\right)^{2}=\frac{169}{4}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{13}{2}\right)^{2}}=\sqrt{\frac{169}{4}}$$

Simplify.

$$x-\frac{13}{2}=\frac{13}{2} x-\frac{13}{2}=-\frac{13}{2}$$

Add \frac{13}{2} to both sides of the equation.

$$x=13 x=0$$