Solve x=(x+18/63)*18/63quad5/63

$$x = ( x + \frac { 18 } { 63 } ) \times \frac { 18 } { 63 } \quad \frac { 5 } { 63 }$$

Solve for x

$$x=\frac{20}{3017}\approx 0.006629102$$

Steps for Solving Linear Equation

Reduce the fraction \frac{18}{63} to lowest terms by extracting and canceling out 9.

$$x=\left(x+\frac{2}{7}\right)\times \frac{18}{63}\times \frac{5}{63}$$

Reduce the fraction \frac{18}{63} to lowest terms by extracting and canceling out 9.

$$x=\left(x+\frac{2}{7}\right)\times \frac{2}{7}\times \frac{5}{63}$$

Multiply \frac{2}{7} times \frac{5}{63} by multiplying numerator times numerator and denominator times denominator.

$$x=\left(x+\frac{2}{7}\right)\times \frac{2\times 5}{7\times 63}$$

Do the multiplications in the fraction \frac{2\times 5}{7\times 63}.

$$x=\left(x+\frac{2}{7}\right)\times \frac{10}{441}$$

Use the distributive property to multiply x+\frac{2}{7} by \frac{10}{441}.

$$x=x\times \frac{10}{441}+\frac{2}{7}\times \frac{10}{441}$$

Multiply \frac{2}{7} times \frac{10}{441} by multiplying numerator times numerator and denominator times denominator.

$$x=x\times \frac{10}{441}+\frac{2\times 10}{7\times 441}$$

Do the multiplications in the fraction \frac{2\times 10}{7\times 441}.

$$x=x\times \frac{10}{441}+\frac{20}{3087}$$

Subtract x\times \frac{10}{441} from both sides.

$$x-x\times \frac{10}{441}=\frac{20}{3087}$$

Combine x and -x\times \frac{10}{441} to get \frac{431}{441}x.

$$\frac{431}{441}x=\frac{20}{3087}$$

Multiply both sides by \frac{441}{431}, the reciprocal of \frac{431}{441}.

$$x=\frac{20}{3087}\times \frac{441}{431}$$

Multiply \frac{20}{3087} times \frac{441}{431} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{20\times 441}{3087\times 431}$$

Do the multiplications in the fraction \frac{20\times 441}{3087\times 431}.

$$x=\frac{8820}{1330497}$$

Reduce the fraction \frac{8820}{1330497} to lowest terms by extracting and canceling out 441.

$$x=\frac{20}{3017}$$