Solve for x
x=17-12\sqrt{2}\approx 0.029437252
Assign x
x≔17-12\sqrt{2}
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x=9-12\sqrt{2}+4\left(\sqrt{2}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(3-2\sqrt{2}\right)^{2}.
x=9-12\sqrt{2}+4\times 2
The square of \sqrt{2} is 2.
x=9-12\sqrt{2}+8
Multiply 4 and 2 to get 8.
x=17-12\sqrt{2}
Add 9 and 8 to get 17.
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