Solve x=(-2)^{3}-3^2+[(-1/2)^-3*2^-1]div(1/4)^-1

$$x = ( - 2 ) ^ { 3 } - 3 ^ { 2 } + [ ( - \frac { 1 } { 2 } ) ^ { - 3 } \cdot 2 ^ { - 1 } ] \div ( \frac { 1 } { 4 } ) ^ { - 1 }$$

Solve for x

$$x=-18$$

Steps for Solving Linear Equation

Calculate -2 to the power of 3 and get -8.

$$x=-8-3^{2}+\frac{\left(-\frac{1}{2}\right)^{-3}\times 2^{-1}}{\left(\frac{1}{4}\right)^{-1}}$$

Calculate 3 to the power of 2 and get 9.

$$x=-8-9+\frac{\left(-\frac{1}{2}\right)^{-3}\times 2^{-1}}{\left(\frac{1}{4}\right)^{-1}}$$

Subtract 9 from -8 to get -17.

$$x=-17+\frac{\left(-\frac{1}{2}\right)^{-3}\times 2^{-1}}{\left(\frac{1}{4}\right)^{-1}}$$

Calculate -\frac{1}{2} to the power of -3 and get -8.

$$x=-17+\frac{-8\times 2^{-1}}{\left(\frac{1}{4}\right)^{-1}}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$x=-17+\frac{-8\times \frac{1}{2}}{\left(\frac{1}{4}\right)^{-1}}$$

Multiply -8 and \frac{1}{2} to get -4.

$$x=-17+\frac{-4}{\left(\frac{1}{4}\right)^{-1}}$$

Calculate \frac{1}{4} to the power of -1 and get 4.

$$x=-17+\frac{-4}{4}$$

Divide -4 by 4 to get -1.

$$x=-17-1$$

Subtract 1 from -17 to get -18.

$$x=-18$$

Assign x

$$x≔-18$$