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Solve for k_1
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x=8-\frac{8}{3}k_{1}
Divide each term of 24-8k_{1} by 3 to get 8-\frac{8}{3}k_{1}.
8-\frac{8}{3}k_{1}=x
Swap sides so that all variable terms are on the left hand side.
-\frac{8}{3}k_{1}=x-8
Subtract 8 from both sides.
\frac{-\frac{8}{3}k_{1}}{-\frac{8}{3}}=\frac{x-8}{-\frac{8}{3}}
Divide both sides of the equation by -\frac{8}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.
k_{1}=\frac{x-8}{-\frac{8}{3}}
Dividing by -\frac{8}{3} undoes the multiplication by -\frac{8}{3}.
k_{1}=-\frac{3x}{8}+3
Divide x-8 by -\frac{8}{3} by multiplying x-8 by the reciprocal of -\frac{8}{3}.
x=8-\frac{8}{3}k_{1}
Divide each term of 24-8k_{1} by 3 to get 8-\frac{8}{3}k_{1}.