Solve x=(3y+3z/6)

$$x = ( \frac { 3 y + 3 z } { 6 } )$$

Solve for y

$$y=2x-z$$

Steps for Solving Linear Equation

Divide each term of 3y+3z by 6 to get \frac{1}{2}y+\frac{1}{2}z.

$$x=\frac{1}{2}y+\frac{1}{2}z$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{2}y+\frac{1}{2}z=x$$

Subtract \frac{1}{2}z from both sides.

$$\frac{1}{2}y=x-\frac{1}{2}z$$

The equation is in standard form.

$$\frac{1}{2}y=-\frac{z}{2}+x$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{-\frac{z}{2}+x}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$y=\frac{-\frac{z}{2}+x}{\frac{1}{2}}$$

Divide x-\frac{z}{2} by \frac{1}{2} by multiplying x-\frac{z}{2} by the reciprocal of \frac{1}{2}.

$$y=2x-z$$

Solve for x

$$x=\frac{y+z}{2}$$

Solution Steps

Divide each term of 3y+3z by 6 to get \frac{1}{2}y+\frac{1}{2}z.

$$x=\frac{1}{2}y+\frac{1}{2}z$$