Solve x=(-1/3)^3+[3^-1-(-3)^-1]^-2

$$x = ( \frac { - 1 } { 3 } ) ^ { 3 } + [ 3 ^ { - 1 } - ( - 3 ) ^ { - 1 } ] ^ { - 2 }$$

Solve for x

$$x = \frac{239}{108} = 2\frac{23}{108} \approx 2.212962963$$

Steps for Solving Linear Equation

Fraction \frac{-1}{3} can be rewritten as -\frac{1}{3} by extracting the negative sign.

$$x=\left(-\frac{1}{3}\right)^{3}+\left(3^{-1}-\left(-3\right)^{-1}\right)^{-2}$$

Calculate -\frac{1}{3} to the power of 3 and get -\frac{1}{27}.

$$x=-\frac{1}{27}+\left(3^{-1}-\left(-3\right)^{-1}\right)^{-2}$$

Calculate 3 to the power of -1 and get \frac{1}{3}.

$$x=-\frac{1}{27}+\left(\frac{1}{3}-\left(-3\right)^{-1}\right)^{-2}$$

Calculate -3 to the power of -1 and get -\frac{1}{3}.

$$x=-\frac{1}{27}+\left(\frac{1}{3}-\left(-\frac{1}{3}\right)\right)^{-2}$$

The opposite of -\frac{1}{3} is \frac{1}{3}.

$$x=-\frac{1}{27}+\left(\frac{1}{3}+\frac{1}{3}\right)^{-2}$$

Add \frac{1}{3} and \frac{1}{3} to get \frac{2}{3}.

$$x=-\frac{1}{27}+\left(\frac{2}{3}\right)^{-2}$$

Calculate \frac{2}{3} to the power of -2 and get \frac{9}{4}.

$$x=-\frac{1}{27}+\frac{9}{4}$$

Add -\frac{1}{27} and \frac{9}{4} to get \frac{239}{108}.

$$x=\frac{239}{108}$$

Assign x

$$x≔\frac{239}{108}$$