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x^{2}=\left(\sqrt{5x+14}\right)^{2}
Square both sides of the equation.
x^{2}=5x+14
Calculate \sqrt{5x+14} to the power of 2 and get 5x+14.
x^{2}-5x=14
Subtract 5x from both sides.
x^{2}-5x-14=0
Subtract 14 from both sides.
a+b=-5 ab=-14
To solve the equation, factor x^{2}-5x-14 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
1,-14 2,-7
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -14.
1-14=-13 2-7=-5
Calculate the sum for each pair.
a=-7 b=2
The solution is the pair that gives sum -5.
\left(x-7\right)\left(x+2\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=7 x=-2
To find equation solutions, solve x-7=0 and x+2=0.
7=\sqrt{5\times 7+14}
Substitute 7 for x in the equation x=\sqrt{5x+14}.
7=7
Simplify. The value x=7 satisfies the equation.
-2=\sqrt{5\left(-2\right)+14}
Substitute -2 for x in the equation x=\sqrt{5x+14}.
-2=2
Simplify. The value x=-2 does not satisfy the equation because the left and the right hand side have opposite signs.
x=7
Equation x=\sqrt{5x+14} has a unique solution.