Solve x=sqrt{1/1+2*3^2-16+1}

$$x = \sqrt { \frac { 1 } { 1 + 2 \cdot 3 ^ { 2 } - 16 + 1 } }$$

Solve for x

$$x=\frac{1}{2}=0.5$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$x=\sqrt{\frac{1}{1+2\times 9-16+1}}$$

Multiply 2 and 9 to get 18.

$$x=\sqrt{\frac{1}{1+18-16+1}}$$

Add 1 and 18 to get 19.

$$x=\sqrt{\frac{1}{19-16+1}}$$

Subtract 16 from 19 to get 3.

$$x=\sqrt{\frac{1}{3+1}}$$

Add 3 and 1 to get 4.

$$x=\sqrt{\frac{1}{4}}$$

Rewrite the square root of the division \frac{1}{4} as the division of square roots \frac{\sqrt{1}}{\sqrt{4}}. Take the square root of both numerator and denominator.

$$x=\frac{1}{2}$$

Assign x

$$x≔\frac{1}{2}$$