Solve for Δ
\Delta =x^{2}-1
x\geq 0
Solve for Δ (complex solution)
\Delta =x^{2}-1
arg(x)<\pi \text{ or }x=0
Solve for x
x=\sqrt{\Delta +1}
\Delta \geq -1
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\sqrt{\Delta +1}=x
Swap sides so that all variable terms are on the left hand side.
\Delta +1=x^{2}
Square both sides of the equation.
\Delta +1-1=x^{2}-1
Subtract 1 from both sides of the equation.
\Delta =x^{2}-1
Subtracting 1 from itself leaves 0.
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