Solve x=y/3+y

$$x = \frac { y } { 3 + y }$$

Solve for y

$$y=-\frac{3x}{x-1}$$

$$x\neq 1$$

Steps for Solving Linear Equation

Variable y cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by y+3.

$$x\left(y+3\right)=y$$

Use the distributive property to multiply x by y+3.

$$xy+3x=y$$

Subtract y from both sides.

$$xy+3x-y=0$$

Subtract 3x from both sides. Anything subtracted from zero gives its negation.

$$xy-y=-3x$$

Combine all terms containing y.

$$\left(x-1\right)y=-3x$$

Divide both sides by x-1.

$$\frac{\left(x-1\right)y}{x-1}=-\frac{3x}{x-1}$$

Dividing by x-1 undoes the multiplication by x-1.

$$y=-\frac{3x}{x-1}$$

Variable y cannot be equal to -3.

$$y=-\frac{3x}{x-1}\text{, }y\neq -3$$

Solve for x

$$x=\frac{y}{y+3}$$

$$y\neq -3$$