Solve x=y+3/3

$$x = \frac { y + 3 } { 3 }$$

Solve for y

$$y=3\left(x-1\right)$$

Steps for Solving Linear Equation

Divide each term of y+3 by 3 to get \frac{1}{3}y+1.

$$x=\frac{1}{3}y+1$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{1}{3}y+1=x$$

Subtract 1 from both sides.

$$\frac{1}{3}y=x-1$$

Multiply both sides by 3.

$$\frac{\frac{1}{3}y}{\frac{1}{3}}=\frac{x-1}{\frac{1}{3}}$$

Dividing by \frac{1}{3} undoes the multiplication by \frac{1}{3}.

$$y=\frac{x-1}{\frac{1}{3}}$$

Divide x-1 by \frac{1}{3} by multiplying x-1 by the reciprocal of \frac{1}{3}.

$$y=3x-3$$

Solve for x

$$x=\frac{y+3}{3}$$

Solution Steps

Divide each term of y+3 by 3 to get \frac{1}{3}y+1.

$$x=\frac{1}{3}y+1$$