Solve x=x^2+3/x+5

$$x = \frac { x ^ { 2 } + 3 } { x + 5 }$$

Solve for x

$$x=\frac{3}{5}=0.6$$

Steps for Solving Linear Equation

Subtract \frac{x^{2}+3}{x+5} from both sides.

$$x-\frac{x^{2}+3}{x+5}=0$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x times \frac{x+5}{x+5}.

$$\frac{x\left(x+5\right)}{x+5}-\frac{x^{2}+3}{x+5}=0$$

Since \frac{x\left(x+5\right)}{x+5} and \frac{x^{2}+3}{x+5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x\left(x+5\right)-\left(x^{2}+3\right)}{x+5}=0$$

Do the multiplications in x\left(x+5\right)-\left(x^{2}+3\right).

$$\frac{x^{2}+5x-x^{2}-3}{x+5}=0$$

Combine like terms in x^{2}+5x-x^{2}-3.

$$\frac{5x-3}{x+5}=0$$

Variable x cannot be equal to -5 since division by zero is not defined. Multiply both sides of the equation by x+5.

$$5x-3=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$5x=3$$

Divide both sides by 5.

$$x=\frac{3}{5}$$