Solve x=p-2/2*(-5)^-2

$$x = \frac { p - 2 } { 2 \cdot ( - 5 ) ^ { - 2 } }$$

Solve for p

$$p=\frac{2\left(x+25\right)}{25}$$

Steps for Solving Linear Equation

Calculate -5 to the power of -2 and get \frac{1}{25}.

$$x=\frac{p-2}{2\times \frac{1}{25}}$$

Multiply 2 and \frac{1}{25} to get \frac{2}{25}.

$$x=\frac{p-2}{\frac{2}{25}}$$

Divide each term of p-2 by \frac{2}{25} to get \frac{p}{\frac{2}{25}}+\frac{-2}{\frac{2}{25}}.

$$x=\frac{p}{\frac{2}{25}}+\frac{-2}{\frac{2}{25}}$$

Divide -2 by \frac{2}{25} by multiplying -2 by the reciprocal of \frac{2}{25}.

$$x=\frac{p}{\frac{2}{25}}-2\times \frac{25}{2}$$

Multiply -2 and \frac{25}{2} to get -25.

$$x=\frac{p}{\frac{2}{25}}-25$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{p}{\frac{2}{25}}-25=x$$

Add 25 to both sides.

$$\frac{p}{\frac{2}{25}}=x+25$$

The equation is in standard form.

$$\frac{25}{2}p=x+25$$

Divide both sides of the equation by \frac{25}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{25}{2}p}{\frac{25}{2}}=\frac{x+25}{\frac{25}{2}}$$

Dividing by \frac{25}{2} undoes the multiplication by \frac{25}{2}.

$$p=\frac{x+25}{\frac{25}{2}}$$

Divide x+25 by \frac{25}{2} by multiplying x+25 by the reciprocal of \frac{25}{2}.

$$p=\frac{2x}{25}+2$$

Solve for x

$$x=\frac{25\left(p-2\right)}{2}$$