Solve x=frac{6+sqrt{6^2-32}}{2*4}

$$x = \frac { 6 + \sqrt { 6 ^ { 2 } - 32 } } { 2 \cdot 4 }$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Calculate 6 to the power of 2 and get 36.

$$x=\frac{6+\sqrt{36-32}}{2\times 4}$$

Subtract 32 from 36 to get 4.

$$x=\frac{6+\sqrt{4}}{2\times 4}$$

Calculate the square root of 4 and get 2.

$$x=\frac{6+2}{2\times 4}$$

Add 6 and 2 to get 8.

$$x=\frac{8}{2\times 4}$$

Multiply 2 and 4 to get 8.

$$x=\frac{8}{8}$$

Divide 8 by 8 to get 1.

$$x=1$$

Assign x

$$x≔1$$