Solve x=2/90+2/72+quad-2/20+2/12

$$x = \frac { 2 } { 90 } + \frac { 2 } { 72 } + \quad - \frac { 2 } { 20 } + \frac { 2 } { 12 }$$

Solve for x

$$x=\frac{7}{60}\approx 0.116666667$$

Steps for Solving Linear Equation

Reduce the fraction \frac{2}{90} to lowest terms by extracting and canceling out 2.

$$x=\frac{1}{45}+\frac{2}{72}-\frac{2}{20}+\frac{2}{12}$$

Reduce the fraction \frac{2}{72} to lowest terms by extracting and canceling out 2.

$$x=\frac{1}{45}+\frac{1}{36}-\frac{2}{20}+\frac{2}{12}$$

Least common multiple of 45 and 36 is 180. Convert \frac{1}{45} and \frac{1}{36} to fractions with denominator 180.

$$x=\frac{4}{180}+\frac{5}{180}-\frac{2}{20}+\frac{2}{12}$$

Since \frac{4}{180} and \frac{5}{180} have the same denominator, add them by adding their numerators.

$$x=\frac{4+5}{180}-\frac{2}{20}+\frac{2}{12}$$

Add 4 and 5 to get 9.

$$x=\frac{9}{180}-\frac{2}{20}+\frac{2}{12}$$

Reduce the fraction \frac{9}{180} to lowest terms by extracting and canceling out 9.

$$x=\frac{1}{20}-\frac{2}{20}+\frac{2}{12}$$

Reduce the fraction \frac{2}{20} to lowest terms by extracting and canceling out 2.

$$x=\frac{1}{20}-\frac{1}{10}+\frac{2}{12}$$

Least common multiple of 20 and 10 is 20. Convert \frac{1}{20} and \frac{1}{10} to fractions with denominator 20.

$$x=\frac{1}{20}-\frac{2}{20}+\frac{2}{12}$$

Since \frac{1}{20} and \frac{2}{20} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{1-2}{20}+\frac{2}{12}$$

Subtract 2 from 1 to get -1.

$$x=-\frac{1}{20}+\frac{2}{12}$$

Reduce the fraction \frac{2}{12} to lowest terms by extracting and canceling out 2.

$$x=-\frac{1}{20}+\frac{1}{6}$$

Least common multiple of 20 and 6 is 60. Convert -\frac{1}{20} and \frac{1}{6} to fractions with denominator 60.

$$x=-\frac{3}{60}+\frac{10}{60}$$

Since -\frac{3}{60} and \frac{10}{60} have the same denominator, add them by adding their numerators.

$$x=\frac{-3+10}{60}$$

Add -3 and 10 to get 7.

$$x=\frac{7}{60}$$

Assign x

$$x≔\frac{7}{60}$$