Solve x=12-2y/-3

$$x = \frac { 12 - 2 y } { - 3 }$$

Solve for y

$$y=\frac{3\left(x+4\right)}{2}$$

Steps for Solving Linear Equation

Divide each term of 12-2y by -3 to get -4+\frac{2}{3}y.

$$x=-4+\frac{2}{3}y$$

Swap sides so that all variable terms are on the left hand side.

$$-4+\frac{2}{3}y=x$$

Add 4 to both sides.

$$\frac{2}{3}y=x+4$$

Divide both sides of the equation by \frac{2}{3}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{2}{3}y}{\frac{2}{3}}=\frac{x+4}{\frac{2}{3}}$$

Dividing by \frac{2}{3} undoes the multiplication by \frac{2}{3}.

$$y=\frac{x+4}{\frac{2}{3}}$$

Divide x+4 by \frac{2}{3} by multiplying x+4 by the reciprocal of \frac{2}{3}.

$$y=\frac{3x}{2}+6$$

Solve for x

$$x=\frac{2\left(y-6\right)}{3}$$

Solution Steps

Divide each term of 12-2y by -3 to get -4+\frac{2}{3}y.

$$x=-4+\frac{2}{3}y$$