Solve x=-y/1-3y

$$x = \frac { - y } { 1 - 3 y }$$

Solve for y

$$y=-\frac{x}{1-3x}$$

$$x\neq \frac{1}{3}$$

Steps for Solving Linear Equation

Variable y cannot be equal to \frac{1}{3} since division by zero is not defined. Multiply both sides of the equation by -3y+1.

$$x\left(-3y+1\right)=-y$$

Use the distributive property to multiply x by -3y+1.

$$-3xy+x=-y$$

Add y to both sides.

$$-3xy+x+y=0$$

Subtract x from both sides. Anything subtracted from zero gives its negation.

$$-3xy+y=-x$$

Combine all terms containing y.

$$\left(-3x+1\right)y=-x$$

The equation is in standard form.

$$\left(1-3x\right)y=-x$$

Divide both sides by -3x+1.

$$\frac{\left(1-3x\right)y}{1-3x}=-\frac{x}{1-3x}$$

Dividing by -3x+1 undoes the multiplication by -3x+1.

$$y=-\frac{x}{1-3x}$$

Variable y cannot be equal to \frac{1}{3}.

$$y=-\frac{x}{1-3x}\text{, }y\neq \frac{1}{3}$$

Solve for x

$$x=-\frac{y}{1-3y}$$

$$y\neq \frac{1}{3}$$