Solve x=[7sqrt{2}]^2*[3.4*90/360-1/2]

$$x = [ 7 \sqrt { 2 } ] ^ { 2 } \times [ \frac { 3.4 \times 90 } { 360 } - \frac { 1 } { 2 } ]$$

Solve for x

$$x=34.3$$

Steps for Solving Linear Equation

Expand \left(7\sqrt{2}\right)^{2}.

$$x=7^{2}\left(\sqrt{2}\right)^{2}\left(\frac{3.4\times 90}{360}-\frac{1}{2}\right)$$

Calculate 7 to the power of 2 and get 49.

$$x=49\left(\sqrt{2}\right)^{2}\left(\frac{3.4\times 90}{360}-\frac{1}{2}\right)$$

The square of \sqrt{2} is 2.

$$x=49\times 2\left(\frac{3.4\times 90}{360}-\frac{1}{2}\right)$$

Multiply 49 and 2 to get 98.

$$x=98\left(\frac{3.4\times 90}{360}-\frac{1}{2}\right)$$

Multiply 3.4 and 90 to get 306.

$$x=98\left(\frac{306}{360}-\frac{1}{2}\right)$$

Reduce the fraction \frac{306}{360} to lowest terms by extracting and canceling out 18.

$$x=98\left(\frac{17}{20}-\frac{1}{2}\right)$$

Subtract \frac{1}{2} from \frac{17}{20} to get \frac{7}{20}.

$$x=98\times \frac{7}{20}$$

Multiply 98 and \frac{7}{20} to get \frac{343}{10}.

$$x=\frac{343}{10}$$

Assign x

$$x≔34.3$$