Solve x=[2^9:(2^2*2)^3]^-3

$$x = [ 2 ^ { 9 } : ( 2 ^ { 2 } \cdot 2 ) ^ { 3 } ] ^ { - 3 }$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$x=\left(\frac{2^{9}}{\left(2^{3}\right)^{3}}\right)^{-3}$$

To raise a power to another power, multiply the exponents. Multiply 3 and 3 to get 9.

$$x=\left(\frac{2^{9}}{2^{9}}\right)^{-3}$$

Cancel out 2^{9} in both numerator and denominator.

$$x=1^{-3}$$

Calculate 1 to the power of -3 and get 1.

$$x=1$$

Assign x

$$x≔1$$