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x^{2}=\left(\sqrt{7x+8}\right)^{2}
Square both sides of the equation.
x^{2}=7x+8
Calculate \sqrt{7x+8} to the power of 2 and get 7x+8.
x^{2}-7x=8
Subtract 7x from both sides.
x^{2}-7x-8=0
Subtract 8 from both sides.
a+b=-7 ab=-8
To solve the equation, factor x^{2}-7x-8 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
1,-8 2,-4
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -8.
1-8=-7 2-4=-2
Calculate the sum for each pair.
a=-8 b=1
The solution is the pair that gives sum -7.
\left(x-8\right)\left(x+1\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=8 x=-1
To find equation solutions, solve x-8=0 and x+1=0.
8=\sqrt{7\times 8+8}
Substitute 8 for x in the equation x=\sqrt{7x+8}.
8=8
Simplify. The value x=8 satisfies the equation.
-1=\sqrt{7\left(-1\right)+8}
Substitute -1 for x in the equation x=\sqrt{7x+8}.
-1=1
Simplify. The value x=-1 does not satisfy the equation because the left and the right hand side have opposite signs.
x=8
Equation x=\sqrt{7x+8} has a unique solution.