Solve x=sqrt{left(2-3right)^2+left(2-3right)^2+left(2-3right)^2+left(2-3right)^2}

$$x = \sqrt{ { \left(2-3 \right) }^{ 2 } + { \left(2-3 \right) }^{ 2 } + { \left(2-3 \right) }^{ 2 } + { \left(2-3 \right) }^{ 2 } }$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Subtract 3 from 2 to get -1.

$$x=\sqrt{\left(-1\right)^{2}+\left(2-3\right)^{2}+\left(2-3\right)^{2}+\left(2-3\right)^{2}}$$

Calculate -1 to the power of 2 and get 1.

$$x=\sqrt{1+\left(2-3\right)^{2}+\left(2-3\right)^{2}+\left(2-3\right)^{2}}$$

Subtract 3 from 2 to get -1.

$$x=\sqrt{1+\left(-1\right)^{2}+\left(2-3\right)^{2}+\left(2-3\right)^{2}}$$

Calculate -1 to the power of 2 and get 1.

$$x=\sqrt{1+1+\left(2-3\right)^{2}+\left(2-3\right)^{2}}$$

Add 1 and 1 to get 2.

$$x=\sqrt{2+\left(2-3\right)^{2}+\left(2-3\right)^{2}}$$

Subtract 3 from 2 to get -1.

$$x=\sqrt{2+\left(-1\right)^{2}+\left(2-3\right)^{2}}$$

Calculate -1 to the power of 2 and get 1.

$$x=\sqrt{2+1+\left(2-3\right)^{2}}$$

Add 2 and 1 to get 3.

$$x=\sqrt{3+\left(2-3\right)^{2}}$$

Subtract 3 from 2 to get -1.

$$x=\sqrt{3+\left(-1\right)^{2}}$$

Calculate -1 to the power of 2 and get 1.

$$x=\sqrt{3+1}$$

Add 3 and 1 to get 4.

$$x=\sqrt{4}$$

Calculate the square root of 4 and get 2.

$$x=2$$

Assign x

$$x≔2$$