Solve for x
x = \frac{\sqrt{7} + 3}{2} \approx 2.822875656
Assign x
x≔\frac{\sqrt{7}+3}{2}
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x=\frac{6+\sqrt{36-4\times 2\times 1}}{2\times 2}
Calculate -6 to the power of 2 and get 36.
x=\frac{6+\sqrt{36-8\times 1}}{2\times 2}
Multiply 4 and 2 to get 8.
x=\frac{6+\sqrt{36-8}}{2\times 2}
Multiply 8 and 1 to get 8.
x=\frac{6+\sqrt{28}}{2\times 2}
Subtract 8 from 36 to get 28.
x=\frac{6+2\sqrt{7}}{2\times 2}
Factor 28=2^{2}\times 7. Rewrite the square root of the product \sqrt{2^{2}\times 7} as the product of square roots \sqrt{2^{2}}\sqrt{7}. Take the square root of 2^{2}.
x=\frac{6+2\sqrt{7}}{4}
Multiply 2 and 2 to get 4.
x=\frac{3}{2}+\frac{1}{2}\sqrt{7}
Divide each term of 6+2\sqrt{7} by 4 to get \frac{3}{2}+\frac{1}{2}\sqrt{7}.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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