Solve x=3/40left(320-2left(2x+2left(x-5right)right)right)

$$x = \frac{ 3 }{ 40 } \left( 320-2 \left( 2x+2 \left( x-5 \right) \right) \right)$$

Solve for x

$$x = \frac{255}{16} = 15\frac{15}{16} = 15.9375$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by x-5.

$$x=\frac{3}{40}\left(320-2\left(2x+2x-10\right)\right)$$

Combine 2x and 2x to get 4x.

$$x=\frac{3}{40}\left(320-2\left(4x-10\right)\right)$$

Use the distributive property to multiply -2 by 4x-10.

$$x=\frac{3}{40}\left(320-8x+20\right)$$

Add 320 and 20 to get 340.

$$x=\frac{3}{40}\left(340-8x\right)$$

Use the distributive property to multiply \frac{3}{40} by 340-8x.

$$x=\frac{3}{40}\times 340+\frac{3}{40}\left(-8\right)x$$

Express \frac{3}{40}\times 340 as a single fraction.

$$x=\frac{3\times 340}{40}+\frac{3}{40}\left(-8\right)x$$

Multiply 3 and 340 to get 1020.

$$x=\frac{1020}{40}+\frac{3}{40}\left(-8\right)x$$

Reduce the fraction \frac{1020}{40} to lowest terms by extracting and canceling out 20.

$$x=\frac{51}{2}+\frac{3}{40}\left(-8\right)x$$

Express \frac{3}{40}\left(-8\right) as a single fraction.

$$x=\frac{51}{2}+\frac{3\left(-8\right)}{40}x$$

Multiply 3 and -8 to get -24.

$$x=\frac{51}{2}+\frac{-24}{40}x$$

Reduce the fraction \frac{-24}{40} to lowest terms by extracting and canceling out 8.

$$x=\frac{51}{2}-\frac{3}{5}x$$

Add \frac{3}{5}x to both sides.

$$x+\frac{3}{5}x=\frac{51}{2}$$

Combine x and \frac{3}{5}x to get \frac{8}{5}x.

$$\frac{8}{5}x=\frac{51}{2}$$

Multiply both sides by \frac{5}{8}, the reciprocal of \frac{8}{5}.

$$x=\frac{51}{2}\times \frac{5}{8}$$

Multiply \frac{51}{2} times \frac{5}{8} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{51\times 5}{2\times 8}$$

Do the multiplications in the fraction \frac{51\times 5}{2\times 8}.

$$x=\frac{255}{16}$$