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x=\frac{4\times 2x^{2}}{4\left(2x-1\right)}+\frac{2x-1}{4\left(2x-1\right)}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 2x-1 and 4 is 4\left(2x-1\right). Multiply \frac{2x^{2}}{2x-1} times \frac{4}{4}. Multiply \frac{1}{4} times \frac{2x-1}{2x-1}.
x=\frac{4\times 2x^{2}+2x-1}{4\left(2x-1\right)}
Since \frac{4\times 2x^{2}}{4\left(2x-1\right)} and \frac{2x-1}{4\left(2x-1\right)} have the same denominator, add them by adding their numerators.
x=\frac{8x^{2}+2x-1}{4\left(2x-1\right)}
Do the multiplications in 4\times 2x^{2}+2x-1.
x=\frac{8x^{2}+2x-1}{8x-4}
Use the distributive property to multiply 4 by 2x-1.
x-\frac{8x^{2}+2x-1}{8x-4}=0
Subtract \frac{8x^{2}+2x-1}{8x-4} from both sides.
x-\frac{8x^{2}+2x-1}{4\left(2x-1\right)}=0
Factor 8x-4.
\frac{x\times 4\left(2x-1\right)}{4\left(2x-1\right)}-\frac{8x^{2}+2x-1}{4\left(2x-1\right)}=0
To add or subtract expressions, expand them to make their denominators the same. Multiply x times \frac{4\left(2x-1\right)}{4\left(2x-1\right)}.
\frac{x\times 4\left(2x-1\right)-\left(8x^{2}+2x-1\right)}{4\left(2x-1\right)}=0
Since \frac{x\times 4\left(2x-1\right)}{4\left(2x-1\right)} and \frac{8x^{2}+2x-1}{4\left(2x-1\right)} have the same denominator, subtract them by subtracting their numerators.
\frac{8x^{2}-4x-8x^{2}-2x+1}{4\left(2x-1\right)}=0
Do the multiplications in x\times 4\left(2x-1\right)-\left(8x^{2}+2x-1\right).
\frac{-6x+1}{4\left(2x-1\right)}=0
Combine like terms in 8x^{2}-4x-8x^{2}-2x+1.
-6x+1=0
Variable x cannot be equal to \frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by 4\left(2x-1\right).
-6x=-1
Subtract 1 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-1}{-6}
Divide both sides by -6.
x=\frac{1}{6}
Fraction \frac{-1}{-6} can be simplified to \frac{1}{6} by removing the negative sign from both the numerator and the denominator.