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x=\frac{12x+\sqrt{-12x^{2}-20x^{2}\times 50}}{2}
Multiply 4 and 5 to get 20.
x=\frac{12x+\sqrt{-12x^{2}-1000x^{2}}}{2}
Multiply 20 and 50 to get 1000.
x=\frac{12x+\sqrt{-1012x^{2}}}{2}
Combine -12x^{2} and -1000x^{2} to get -1012x^{2}.
x-\frac{12x+\sqrt{-1012x^{2}}}{2}=0
Subtract \frac{12x+\sqrt{-1012x^{2}}}{2} from both sides.
2x-\left(12x+\sqrt{-1012x^{2}}\right)=0
Multiply both sides of the equation by 2.
2x-12x-\sqrt{-1012x^{2}}=0
To find the opposite of 12x+\sqrt{-1012x^{2}}, find the opposite of each term.
-10x-\sqrt{-1012x^{2}}=0
Combine 2x and -12x to get -10x.
-\sqrt{-1012x^{2}}=10x
Subtract -10x from both sides of the equation.
\left(-\sqrt{-1012x^{2}}\right)^{2}=\left(10x\right)^{2}
Square both sides of the equation.
\left(-1\right)^{2}\left(\sqrt{-1012x^{2}}\right)^{2}=\left(10x\right)^{2}
Expand \left(-\sqrt{-1012x^{2}}\right)^{2}.
1\left(\sqrt{-1012x^{2}}\right)^{2}=\left(10x\right)^{2}
Calculate -1 to the power of 2 and get 1.
1\left(-1012\right)x^{2}=\left(10x\right)^{2}
Calculate \sqrt{-1012x^{2}} to the power of 2 and get -1012x^{2}.
-1012x^{2}=\left(10x\right)^{2}
Multiply 1 and -1012 to get -1012.
-1012x^{2}=10^{2}x^{2}
Expand \left(10x\right)^{2}.
-1012x^{2}=100x^{2}
Calculate 10 to the power of 2 and get 100.
-1012x^{2}-100x^{2}=0
Subtract 100x^{2} from both sides.
-1112x^{2}=0
Combine -1012x^{2} and -100x^{2} to get -1112x^{2}.
x^{2}=0
Divide both sides by -1112. Zero divided by any non-zero number gives zero.
x=0 x=0
Take the square root of both sides of the equation.
x=0
The equation is now solved. Solutions are the same.
0=\frac{12\times 0+\sqrt{-12\times 0^{2}-4\times 5\times 0^{2}\times 50}}{2}
Substitute 0 for x in the equation x=\frac{12x+\sqrt{-12x^{2}-4\times 5x^{2}\times 50}}{2}.
0=0
Simplify. The value x=0 satisfies the equation.
x=0
Equation -\sqrt{-1012x^{2}}=10x has a unique solution.