Solve x=1/2^2+1/y

$$x = \frac{ 1 }{ { 2 }^{ 2 } } + \frac{ 1 }{ y }$$

Solve for y

$$y=-\frac{4}{1-4x}$$

$$x\neq \frac{1}{4}$$

Steps for Solving Linear Equation

Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.

$$xy=\frac{1}{4}y+1$$

Subtract \frac{1}{4}y from both sides.

$$xy-\frac{1}{4}y=1$$

Combine all terms containing y.

$$\left(x-\frac{1}{4}\right)y=1$$

Divide both sides by x-\frac{1}{4}.

$$\frac{\left(x-\frac{1}{4}\right)y}{x-\frac{1}{4}}=\frac{1}{x-\frac{1}{4}}$$

Dividing by x-\frac{1}{4} undoes the multiplication by x-\frac{1}{4}.

$$y=\frac{1}{x-\frac{1}{4}}$$

Divide 1 by x-\frac{1}{4}.

$$y=\frac{4}{4x-1}$$

Variable y cannot be equal to 0.

$$y=\frac{4}{4x-1}\text{, }y\neq 0$$

Solve for x

$$x=\frac{1}{4}+\frac{1}{y}$$

$$y\neq 0$$