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Solve for y
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x\left(2y+1\right)=-3y-2
Variable y cannot be equal to -\frac{1}{2} since division by zero is not defined. Multiply both sides of the equation by 2y+1.
2xy+x=-3y-2
Use the distributive property to multiply x by 2y+1.
2xy+x+3y=-2
Add 3y to both sides.
2xy+3y=-2-x
Subtract x from both sides.
\left(2x+3\right)y=-2-x
Combine all terms containing y.
\left(2x+3\right)y=-x-2
The equation is in standard form.
\frac{\left(2x+3\right)y}{2x+3}=\frac{-x-2}{2x+3}
Divide both sides by 2x+3.
y=\frac{-x-2}{2x+3}
Dividing by 2x+3 undoes the multiplication by 2x+3.
y=-\frac{x+2}{2x+3}
Divide -2-x by 2x+3.
y=-\frac{x+2}{2x+3}\text{, }y\neq -\frac{1}{2}
Variable y cannot be equal to -\frac{1}{2}.