Solve for x
x=-\frac{y}{3}-\alpha +60
Solve for y
y=180-3\alpha -3x
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3x+y+3\alpha =180
Combine x and 2x to get 3x.
3x+3\alpha =180-y
Subtract y from both sides.
3x=180-y-3\alpha
Subtract 3\alpha from both sides.
3x=180-3\alpha -y
The equation is in standard form.
\frac{3x}{3}=\frac{180-3\alpha -y}{3}
Divide both sides by 3.
x=\frac{180-3\alpha -y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{y}{3}-\alpha +60
Divide 180-y-3\alpha by 3.
3x+y+3\alpha =180
Combine x and 2x to get 3x.
y+3\alpha =180-3x
Subtract 3x from both sides.
y=180-3x-3\alpha
Subtract 3\alpha from both sides.
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