Solve for s (complex solution)
\left\{\begin{matrix}s=-\frac{x+3c-1}{y}\text{, }&y\neq 0\\s\in \mathrm{C}\text{, }&x=1-3c\text{ and }y=0\end{matrix}\right.
Solve for c
c=\frac{1-sy-x}{3}
Solve for s
\left\{\begin{matrix}s=-\frac{x+3c-1}{y}\text{, }&y\neq 0\\s\in \mathrm{R}\text{, }&x=1-3c\text{ and }y=0\end{matrix}\right.
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sy+3c=1-x
Subtract x from both sides.
sy=1-x-3c
Subtract 3c from both sides.
ys=1-3c-x
The equation is in standard form.
\frac{ys}{y}=\frac{1-3c-x}{y}
Divide both sides by y.
s=\frac{1-3c-x}{y}
Dividing by y undoes the multiplication by y.
sy+3c=1-x
Subtract x from both sides.
3c=1-x-sy
Subtract sy from both sides.
3c=1-sy-x
The equation is in standard form.
\frac{3c}{3}=\frac{1-sy-x}{3}
Divide both sides by 3.
c=\frac{1-sy-x}{3}
Dividing by 3 undoes the multiplication by 3.
sy+3c=1-x
Subtract x from both sides.
sy=1-x-3c
Subtract 3c from both sides.
ys=1-3c-x
The equation is in standard form.
\frac{ys}{y}=\frac{1-3c-x}{y}
Divide both sides by y.
s=\frac{1-3c-x}{y}
Dividing by y undoes the multiplication by y.
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