Solve x+9^2=(7*9)+(sqrt{13*26*32/4^2})

$$x + 9 ^ { 2 } = ( 7 \times 9 ) + ( \sqrt { \frac { 13 \times 26 \times 32 } { 4 ^ { 2 } } } )$$

Solve for x

$$x=8$$

Steps for Solving Linear Equation

Calculate 9 to the power of 2 and get 81.

$$x+81=7\times 9+\sqrt{\frac{13\times 26\times 32}{4^{2}}}$$

Multiply 7 and 9 to get 63.

$$x+81=63+\sqrt{\frac{13\times 26\times 32}{4^{2}}}$$

Multiply 13 and 26 to get 338.

$$x+81=63+\sqrt{\frac{338\times 32}{4^{2}}}$$

Multiply 338 and 32 to get 10816.

$$x+81=63+\sqrt{\frac{10816}{4^{2}}}$$

Calculate 4 to the power of 2 and get 16.

$$x+81=63+\sqrt{\frac{10816}{16}}$$

Divide 10816 by 16 to get 676.

$$x+81=63+\sqrt{676}$$

Calculate the square root of 676 and get 26.

$$x+81=63+26$$

Add 63 and 26 to get 89.

$$x+81=89$$

Subtract 81 from both sides.

$$x=89-81$$

Subtract 81 from 89 to get 8.

$$x=8$$