Solve x+4quady=1/4x-4quady=

$$x + 4 \quad y = \frac { 1 } { 4 } x - 4 \quad y =$$

Solve for x

$$x=-\frac{32y}{3}$$

Steps for Solving Linear Equation

Subtract \frac{1}{4}x from both sides.

$$x+4y-\frac{1}{4}x=-4y$$

Combine x and -\frac{1}{4}x to get \frac{3}{4}x.

$$\frac{3}{4}x+4y=-4y$$

Subtract 4y from both sides.

$$\frac{3}{4}x=-4y-4y$$

Combine -4y and -4y to get -8y.

$$\frac{3}{4}x=-8y$$

Divide both sides of the equation by \frac{3}{4}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{4}x}{\frac{3}{4}}=-\frac{8y}{\frac{3}{4}}$$

Dividing by \frac{3}{4} undoes the multiplication by \frac{3}{4}.

$$x=-\frac{8y}{\frac{3}{4}}$$

Divide -8y by \frac{3}{4} by multiplying -8y by the reciprocal of \frac{3}{4}.

$$x=-\frac{32y}{3}$$

Solve for y

$$y=-\frac{3x}{32}$$

Steps for Solving Linear Equation

Add 4y to both sides.

$$x+4y+4y=\frac{1}{4}x$$

Combine 4y and 4y to get 8y.

$$x+8y=\frac{1}{4}x$$

Subtract x from both sides.

$$8y=\frac{1}{4}x-x$$

Combine \frac{1}{4}x and -x to get -\frac{3}{4}x.

$$8y=-\frac{3}{4}x$$

The equation is in standard form.

$$8y=-\frac{3x}{4}$$

Divide both sides by 8.

$$\frac{8y}{8}=-\frac{\frac{3x}{4}}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$y=-\frac{\frac{3x}{4}}{8}$$

Divide -\frac{3x}{4} by 8.

$$y=-\frac{3x}{32}$$