Solve for x
x=-3y-3
Solve for y
y=-\frac{x}{3}-1
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x+3=-3y
Subtract 3y from both sides. Anything subtracted from zero gives its negation.
x=-3y-3
Subtract 3 from both sides.
3y+3=-x
Subtract x from both sides. Anything subtracted from zero gives its negation.
3y=-x-3
Subtract 3 from both sides.
\frac{3y}{3}=\frac{-x-3}{3}
Divide both sides by 3.
y=\frac{-x-3}{3}
Dividing by 3 undoes the multiplication by 3.
y=-\frac{x}{3}-1
Divide -x-3 by 3.
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