Solve x+3=zx

$$x + 3 = z x$$

Solve for x

$$x=-\frac{3}{1-z}$$

$$z\neq 1$$

Steps for Solving Linear Equation

Subtract zx from both sides.

$$x+3-zx=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$x-zx=-3$$

Combine all terms containing x.

$$\left(1-z\right)x=-3$$

Divide both sides by 1-z.

$$\frac{\left(1-z\right)x}{1-z}=-\frac{3}{1-z}$$

Dividing by 1-z undoes the multiplication by 1-z.

$$x=-\frac{3}{1-z}$$

Solve for z

$$z=\frac{x+3}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$zx=x+3$$

The equation is in standard form.

$$xz=x+3$$

Divide both sides by x.

$$\frac{xz}{x}=\frac{x+3}{x}$$

Dividing by x undoes the multiplication by x.

$$z=\frac{x+3}{x}$$