Solve for b
b=\frac{x+3}{x}
x\neq 0
Solve for x
x=-\frac{3}{1-b}
b\neq 1
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xb=x+3
Swap sides so that all variable terms are on the left hand side.
\frac{xb}{x}=\frac{x+3}{x}
Divide both sides by x.
b=\frac{x+3}{x}
Dividing by x undoes the multiplication by x.
x+3-xb=0
Subtract xb from both sides.
x-xb=-3
Subtract 3 from both sides. Anything subtracted from zero gives its negation.
\left(1-b\right)x=-3
Combine all terms containing x.
\frac{\left(1-b\right)x}{1-b}=-\frac{3}{1-b}
Divide both sides by 1-b.
x=-\frac{3}{1-b}
Dividing by 1-b undoes the multiplication by 1-b.
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