Solve x+3<-3x+10/4

$$x + 3 < - \frac { 3 x + 10 } { 4 }$$

Solve for x

$$x<-\frac{22}{7}$$

Solution Steps

Multiply both sides of the equation by 4. Since 4 is positive, the inequality direction remains the same.

$$4x+12<-\left(3x+10\right)$$

To find the opposite of 3x+10, find the opposite of each term.

$$4x+12<-3x-10$$

Add 3x to both sides.

$$4x+12+3x<-10$$

Combine 4x and 3x to get 7x.

$$7x+12<-10$$

Subtract 12 from both sides.

$$7x<-10-12$$

Subtract 12 from -10 to get -22.

$$7x<-22$$

Divide both sides by 7. Since 7 is positive, the inequality direction remains the same.

$$x<-\frac{22}{7}$$