Solve x+2y+3z=4

$$x + 2 y + 3 z = 4$$

Solve for x

$$x=4-3z-2y$$

Solution Steps

Subtract 2y from both sides.

$$x+3z=4-2y$$

Subtract 3z from both sides.

$$x=4-2y-3z$$

Solve for y

$$y=-\frac{x}{2}-\frac{3z}{2}+2$$

Steps for Solving Linear Equation

Subtract x from both sides.

$$2y+3z=4-x$$

Subtract 3z from both sides.

$$2y=4-x-3z$$

The equation is in standard form.

$$2y=4-3z-x$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{4-3z-x}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{4-3z-x}{2}$$

Divide 4-x-3z by 2.

$$y=-\frac{x}{2}-\frac{3z}{2}+2$$