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xx+x\times 2-8=2x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
x^{2}+x\times 2-8=2x
Multiply x and x to get x^{2}.
x^{2}+x\times 2-8-2x=0
Subtract 2x from both sides.
x^{2}-8=0
Combine x\times 2 and -2x to get 0.
x^{2}=8
Add 8 to both sides. Anything plus zero gives itself.
x=2\sqrt{2} x=-2\sqrt{2}
Take the square root of both sides of the equation.
xx+x\times 2-8=2x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x.
x^{2}+x\times 2-8=2x
Multiply x and x to get x^{2}.
x^{2}+x\times 2-8-2x=0
Subtract 2x from both sides.
x^{2}-8=0
Combine x\times 2 and -2x to get 0.
x=\frac{0±\sqrt{0^{2}-4\left(-8\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-8\right)}}{2}
Square 0.
x=\frac{0±\sqrt{32}}{2}
Multiply -4 times -8.
x=\frac{0±4\sqrt{2}}{2}
Take the square root of 32.
x=2\sqrt{2}
Now solve the equation x=\frac{0±4\sqrt{2}}{2} when ± is plus.
x=-2\sqrt{2}
Now solve the equation x=\frac{0±4\sqrt{2}}{2} when ± is minus.
x=2\sqrt{2} x=-2\sqrt{2}
The equation is now solved.