Solve x+12geq12x-41

$$x + 12 \geq 12 x - 41$$

Solve for x

$$x\leq \frac{53}{11}$$

Solution Steps

Subtract 12x from both sides.

$$x+12-12x\geq -41$$

Combine x and -12x to get -11x.

$$-11x+12\geq -41$$

Subtract 12 from both sides.

$$-11x\geq -41-12$$

Subtract 12 from -41 to get -53.

$$-11x\geq -53$$

Divide both sides by -11. Since -11 is negative, the inequality direction is changed.

$$x\leq \frac{-53}{-11}$$

Fraction \frac{-53}{-11} can be simplified to \frac{53}{11} by removing the negative sign from both the numerator and the denominator.

$$x\leq \frac{53}{11}$$