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Solve for B
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10B=100-x
Subtract x from both sides.
\frac{10B}{10}=\frac{100-x}{10}
Divide both sides by 10.
B=\frac{100-x}{10}
Dividing by 10 undoes the multiplication by 10.
B=-\frac{x}{10}+10
Divide 100-x by 10.
x=100-10B
Subtract 10B from both sides.