Solve x+05

$$x + 05$$

Evaluate

$$x$$

Solution Steps

Multiply 0 and 5 to get 0.

$$x+0$$

Anything plus zero gives itself.

$$x$$

Differentiate w.r.t. x

$$1$$

Steps Using Definition of a Derivative

Multiply 0 and 5 to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+0)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x)$$

The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$