Solve x+9/4x-15/4-6=0

$$x + \frac { 9 } { 4 } x - \frac { 15 } { 4 } - 6 = 0$$

Solve for x

$$x=3$$

Steps for Solving Linear Equation

Combine x and \frac{9}{4}x to get \frac{13}{4}x.

$$\frac{13}{4}x-\frac{15}{4}-6=0$$

Convert 6 to fraction \frac{24}{4}.

$$\frac{13}{4}x-\frac{15}{4}-\frac{24}{4}=0$$

Since -\frac{15}{4} and \frac{24}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13}{4}x+\frac{-15-24}{4}=0$$

Subtract 24 from -15 to get -39.

$$\frac{13}{4}x-\frac{39}{4}=0$$

Add \frac{39}{4} to both sides. Anything plus zero gives itself.

$$\frac{13}{4}x=\frac{39}{4}$$

Multiply both sides by \frac{4}{13}, the reciprocal of \frac{13}{4}.

$$x=\frac{39}{4}\times \frac{4}{13}$$

Multiply \frac{39}{4} times \frac{4}{13} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{39\times 4}{4\times 13}$$

Cancel out 4 in both numerator and denominator.

$$x=\frac{39}{13}$$

Divide 39 by 13 to get 3.

$$x=3$$